Base | Representation |
---|---|
bin | 100101011011100000100… |
… | …0001000100011000111011 |
3 | 200012210101002121211100202 |
4 | 1022313001001010120323 |
5 | 1133241023404323443 |
6 | 14535133145152415 |
7 | 1040443620451601 |
oct | 112670101043073 |
9 | 20183332554322 |
10 | 5144314136123 |
11 | 1703767243a58 |
12 | 6b100448b70b |
13 | 2b4150684b16 |
14 | 13adb3d3b871 |
15 | 8dc3706a7b8 |
hex | 4adc104463b |
5144314136123 has 2 divisors, whose sum is σ = 5144314136124. Its totient is φ = 5144314136122.
The previous prime is 5144314136111. The next prime is 5144314136231. The reversal of 5144314136123 is 3216314134415.
Together with next prime (5144314136231) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5144314136123 - 210 = 5144314135099 is a prime.
It is a super-2 number, since 2×51443141361232 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5144314156123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2572157068061 + 2572157068062.
It is an arithmetic number, because the mean of its divisors is an integer number (2572157068062).
Almost surely, 25144314136123 is an apocalyptic number.
5144314136123 is a deficient number, since it is larger than the sum of its proper divisors (1).
5144314136123 is an equidigital number, since it uses as much as digits as its factorization.
5144314136123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 38.
The spelling of 5144314136123 in words is "five trillion, one hundred forty-four billion, three hundred fourteen million, one hundred thirty-six thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.128 sec. • engine limits •