Base | Representation |
---|---|
bin | 101111111010101100… |
… | …001110000011000001 |
3 | 11220210200021001010012 |
4 | 233322230032003001 |
5 | 1320332314124004 |
6 | 35345215314305 |
7 | 3500664225026 |
oct | 577254160301 |
9 | 156720231105 |
10 | 51450536129 |
11 | 1a902539343 |
12 | 9b7a81b995 |
13 | 4b0c433925 |
14 | 26c123954d |
15 | 1511dbd46e |
hex | bfab0e0c1 |
51450536129 has 2 divisors, whose sum is σ = 51450536130. Its totient is φ = 51450536128.
The previous prime is 51450536117. The next prime is 51450536197. The reversal of 51450536129 is 92163505415.
51450536129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41270735104 + 10179801025 = 203152^2 + 100895^2 .
It is a cyclic number.
It is not a de Polignac number, because 51450536129 - 216 = 51450470593 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (51450536029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25725268064 + 25725268065.
It is an arithmetic number, because the mean of its divisors is an integer number (25725268065).
Almost surely, 251450536129 is an apocalyptic number.
It is an amenable number.
51450536129 is a deficient number, since it is larger than the sum of its proper divisors (1).
51450536129 is an equidigital number, since it uses as much as digits as its factorization.
51450536129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 51450536129 in words is "fifty-one billion, four hundred fifty million, five hundred thirty-six thousand, one hundred twenty-nine".
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