Base | Representation |
---|---|
bin | 100101011101101100111… |
… | …0100010001001111100001 |
3 | 200020020112102021120201012 |
4 | 1022323121310101033201 |
5 | 1133330200421203333 |
6 | 14541232435150305 |
7 | 1041001433610362 |
oct | 112733164211741 |
9 | 20206472246635 |
10 | 5149025178593 |
11 | 170576452998a |
12 | 6b1aba145395 |
13 | 2b47216b0b0a |
14 | 13b2dd8a1b69 |
15 | 8de10944e48 |
hex | 4aed9d113e1 |
5149025178593 has 8 divisors (see below), whose sum is σ = 5152328643840. Its totient is φ = 5145721953120.
The previous prime is 5149025178559. The next prime is 5149025178599. The reversal of 5149025178593 is 3958715209415.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5149025178593 - 232 = 5144730211297 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5149025178599) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65311028 + ... + 65389818.
It is an arithmetic number, because the mean of its divisors is an integer number (644041080480).
Almost surely, 25149025178593 is an apocalyptic number.
It is an amenable number.
5149025178593 is a deficient number, since it is larger than the sum of its proper divisors (3303465247).
5149025178593 is a wasteful number, since it uses less digits than its factorization.
5149025178593 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 119887.
The product of its (nonzero) digits is 13608000, while the sum is 59.
The spelling of 5149025178593 in words is "five trillion, one hundred forty-nine billion, twenty-five million, one hundred seventy-eight thousand, five hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •