Base | Representation |
---|---|
bin | 10111011010110110110011… |
… | …11011001001110001100011 |
3 | 20202100101022102201100201222 |
4 | 23231123121323021301203 |
5 | 23222240120343311233 |
6 | 301310530114045255 |
7 | 13563526535360321 |
oct | 1355333173116143 |
9 | 222311272640658 |
10 | 51500314041443 |
11 | 15456184736463 |
12 | 5939132b7982b |
13 | 22975c6c12607 |
14 | ca08b2860d11 |
15 | 5e499488d898 |
hex | 2ed6d9ec9c63 |
51500314041443 has 4 divisors (see below), whose sum is σ = 52756419262008. Its totient is φ = 50244208820880.
The previous prime is 51500314041439. The next prime is 51500314041479. The reversal of 51500314041443 is 34414041300515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51500314041443 - 22 = 51500314041439 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51500314041413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 628052610221 + ... + 628052610302.
It is an arithmetic number, because the mean of its divisors is an integer number (13189104815502).
Almost surely, 251500314041443 is an apocalyptic number.
51500314041443 is a deficient number, since it is larger than the sum of its proper divisors (1256105220565).
51500314041443 is a wasteful number, since it uses less digits than its factorization.
51500314041443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1256105220564.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 51500314041443 its reverse (34414041300515), we get a palindrome (85914355341958).
The spelling of 51500314041443 in words is "fifty-one trillion, five hundred billion, three hundred fourteen million, forty-one thousand, four hundred forty-three".
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