Base | Representation |
---|---|
bin | 10111011011101111010000… |
… | …01100010110111100010011 |
3 | 20202110021112101100022121010 |
4 | 23231313220030112330103 |
5 | 23223234201230011143 |
6 | 301332501133302003 |
7 | 13565651520453255 |
oct | 1355675014267423 |
9 | 222407471308533 |
10 | 51530618203923 |
11 | 15468015637241 |
12 | 5942b8b934903 |
13 | 229a416301cc1 |
14 | ca2149443cd5 |
15 | 5e566a049a33 |
hex | 2edde8316f13 |
51530618203923 has 4 divisors (see below), whose sum is σ = 68707490938568. Its totient is φ = 34353745469280.
The previous prime is 51530618203903. The next prime is 51530618203991. The reversal of 51530618203923 is 32930281603515.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 51530618203923 - 217 = 51530618072851 is a prime.
It is a super-2 number, since 2×515306182039232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51530618203903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8588436367318 + ... + 8588436367323.
It is an arithmetic number, because the mean of its divisors is an integer number (17176872734642).
Almost surely, 251530618203923 is an apocalyptic number.
51530618203923 is a deficient number, since it is larger than the sum of its proper divisors (17176872734645).
51530618203923 is a wasteful number, since it uses less digits than its factorization.
51530618203923 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17176872734644.
The product of its (nonzero) digits is 1166400, while the sum is 48.
The spelling of 51530618203923 in words is "fifty-one trillion, five hundred thirty billion, six hundred eighteen million, two hundred three thousand, nine hundred twenty-three".
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