Base | Representation |
---|---|
bin | 111010100101100111011100… |
… | …1010111111010101111001011 |
3 | 2111120200100021012102000202012 |
4 | 1311023032321113322233023 |
5 | 1020021341140324000021 |
6 | 5024013244522530135 |
7 | 213356220436534112 |
oct | 16513167127725713 |
9 | 2446610235360665 |
10 | 515343351000011 |
11 | 13a227984736586 |
12 | 49970bb166694b |
13 | 19172891ac2261 |
14 | 9138a736d4c79 |
15 | 3e8a3e34d235b |
hex | 1d4b3b95fabcb |
515343351000011 has 2 divisors, whose sum is σ = 515343351000012. Its totient is φ = 515343351000010.
The previous prime is 515343350999969. The next prime is 515343351000029. The reversal of 515343351000011 is 110000153343515.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 515343351000011 - 214 = 515343350983627 is a prime.
It is not a weakly prime, because it can be changed into another prime (515343551000011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257671675500005 + 257671675500006.
It is an arithmetic number, because the mean of its divisors is an integer number (257671675500006).
Almost surely, 2515343351000011 is an apocalyptic number.
515343351000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
515343351000011 is an equidigital number, since it uses as much as digits as its factorization.
515343351000011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 32.
The spelling of 515343351000011 in words is "five hundred fifteen trillion, three hundred forty-three billion, three hundred fifty-one million, eleven", and thus it is an aban number.
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