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51542134201 is a prime number
BaseRepresentation
bin110000000000001001…
…101000110110111001
311221001001121201001101
4300000021220312321
51321024241243301
635402250451401
73503155624555
oct600011506671
9157031551041
1051542134201
111a94a211328
129ba5433b61
134b253c507c
1426cd480865
151519e63701
hexc00268db9

51542134201 has 2 divisors, whose sum is σ = 51542134202. Its totient is φ = 51542134200.

The previous prime is 51542134181. The next prime is 51542134249. The reversal of 51542134201 is 10243124515.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49240053801 + 2302080400 = 221901^2 + 47980^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51542134201 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 51542134201.

It is not a weakly prime, because it can be changed into another prime (51542134001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25771067100 + 25771067101.

It is an arithmetic number, because the mean of its divisors is an integer number (25771067101).

Almost surely, 251542134201 is an apocalyptic number.

It is an amenable number.

51542134201 is a deficient number, since it is larger than the sum of its proper divisors (1).

51542134201 is an equidigital number, since it uses as much as digits as its factorization.

51542134201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 51542134201 its reverse (10243124515), we get a palindrome (61785258716).

The spelling of 51542134201 in words is "fifty-one billion, five hundred forty-two million, one hundred thirty-four thousand, two hundred one".