Base | Representation |
---|---|
bin | 110000000000010001… |
… | …101011010010110011 |
3 | 11221001012120202111020 |
4 | 300000101223102303 |
5 | 1321030311210311 |
6 | 35402403550523 |
7 | 3503212552032 |
oct | 600021532263 |
9 | 157035522436 |
10 | 51544241331 |
11 | 1a950420460 |
12 | 9ba608b443 |
13 | 4b259821ab |
14 | 26cd86c719 |
15 | 151a22cc06 |
hex | c0046b4b3 |
51544241331 has 32 divisors (see below), whose sum is σ = 77101113600. Its totient is φ = 30364308480.
The previous prime is 51544241249. The next prime is 51544241347. The reversal of 51544241331 is 13314244515.
It is not a de Polignac number, because 51544241331 - 29 = 51544240819 is a prime.
It is a super-2 number, since 2×515442413312 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 51544241292 and 51544241301.
It is not an unprimeable number, because it can be changed into a prime (51544241351) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24555 + ... + 322011.
It is an arithmetic number, because the mean of its divisors is an integer number (2409409800).
Almost surely, 251544241331 is an apocalyptic number.
51544241331 is a deficient number, since it is larger than the sum of its proper divisors (25556872269).
51544241331 is a wasteful number, since it uses less digits than its factorization.
51544241331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 297619.
The product of its digits is 28800, while the sum is 33.
Adding to 51544241331 its reverse (13314244515), we get a palindrome (64858485846).
The spelling of 51544241331 in words is "fifty-one billion, five hundred forty-four million, two hundred forty-one thousand, three hundred thirty-one".
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