Base | Representation |
---|---|
bin | 110000000000101000… |
… | …000110101100110001 |
3 | 11221001121122110112121 |
4 | 300000220012230301 |
5 | 1321033312331003 |
6 | 35403133554241 |
7 | 3503313540145 |
oct | 600050065461 |
9 | 157047573477 |
10 | 51550120753 |
11 | 1a95377678a |
12 | 9ba8045981 |
13 | 4b26c60341 |
14 | 26d055d225 |
15 | 151a9decbd |
hex | c00a06b31 |
51550120753 has 2 divisors, whose sum is σ = 51550120754. Its totient is φ = 51550120752.
The previous prime is 51550120691. The next prime is 51550120789. The reversal of 51550120753 is 35702105515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51063344784 + 486775969 = 225972^2 + 22063^2 .
It is a cyclic number.
It is not a de Polignac number, because 51550120753 - 229 = 51013249841 is a prime.
It is a super-3 number, since 3×515501207533 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (51550120793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25775060376 + 25775060377.
It is an arithmetic number, because the mean of its divisors is an integer number (25775060377).
Almost surely, 251550120753 is an apocalyptic number.
It is an amenable number.
51550120753 is a deficient number, since it is larger than the sum of its proper divisors (1).
51550120753 is an equidigital number, since it uses as much as digits as its factorization.
51550120753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26250, while the sum is 34.
The spelling of 51550120753 in words is "fifty-one billion, five hundred fifty million, one hundred twenty thousand, seven hundred fifty-three".
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