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5155214041 is a prime number
BaseRepresentation
bin1001100110100011…
…00101001011011001
3111022021110000012101
410303101211023121
541024213322131
62211314043401
7241515411355
oct46321451331
914267400171
105155214041
112205a9067a
12bba579561
13642064b13
1436c946465
152028b5c61
hex1334652d9

5155214041 has 2 divisors, whose sum is σ = 5155214042. Its totient is φ = 5155214040.

The previous prime is 5155214021. The next prime is 5155214047. The reversal of 5155214041 is 1404125515.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4116505600 + 1038708441 = 64160^2 + 32229^2 .

It is a cyclic number.

It is not a de Polignac number, because 5155214041 - 219 = 5154689753 is a prime.

It is not a weakly prime, because it can be changed into another prime (5155214047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577607020 + 2577607021.

It is an arithmetic number, because the mean of its divisors is an integer number (2577607021).

Almost surely, 25155214041 is an apocalyptic number.

It is an amenable number.

5155214041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5155214041 is an equidigital number, since it uses as much as digits as its factorization.

5155214041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4000, while the sum is 28.

The square root of 5155214041 is about 71799.8192267919. The cubic root of 5155214041 is about 1727.4901001148.

Adding to 5155214041 its reverse (1404125515), we get a palindrome (6559339556).

The spelling of 5155214041 in words is "five billion, one hundred fifty-five million, two hundred fourteen thousand, forty-one".