Base | Representation |
---|---|
bin | 100101100000100101100… |
… | …0101010010100110000001 |
3 | 200020211112011202010110112 |
4 | 1023001023011102212001 |
5 | 1133430342412331111 |
6 | 14544135305041105 |
7 | 1041311111450402 |
oct | 113011305224601 |
9 | 20224464663415 |
10 | 5155220433281 |
11 | 17083535a1486 |
12 | 6b3148a86195 |
13 | 2b519b061ca9 |
14 | 13b72a5b99a9 |
15 | 8e17479ae8b |
hex | 4b04b152981 |
5155220433281 has 2 divisors, whose sum is σ = 5155220433282. Its totient is φ = 5155220433280.
The previous prime is 5155220433269. The next prime is 5155220433329. The reversal of 5155220433281 is 1823340225515.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3642219571600 + 1513000861681 = 1908460^2 + 1230041^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5155220433281 is a prime.
It is a super-2 number, since 2×51552204332812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5155220433211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577610216640 + 2577610216641.
It is an arithmetic number, because the mean of its divisors is an integer number (2577610216641).
Almost surely, 25155220433281 is an apocalyptic number.
It is an amenable number.
5155220433281 is a deficient number, since it is larger than the sum of its proper divisors (1).
5155220433281 is an equidigital number, since it uses as much as digits as its factorization.
5155220433281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 41.
Adding to 5155220433281 its reverse (1823340225515), we get a palindrome (6978560658796).
The spelling of 5155220433281 in words is "five trillion, one hundred fifty-five billion, two hundred twenty million, four hundred thirty-three thousand, two hundred eighty-one".
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