Base | Representation |
---|---|
bin | 111010100111000111110101… |
… | …1100110100100100000101011 |
3 | 2111121102010120110120002000112 |
4 | 1311032033223212210200223 |
5 | 1020033234110121212024 |
6 | 5024252321231324535 |
7 | 213410166222244052 |
oct | 16516175346444053 |
9 | 2447363513502015 |
10 | 515550352132139 |
11 | 13a2a7749454995 |
12 | 499a514198074b |
13 | 1918926072275c |
14 | 9144aad549399 |
15 | 3e909ab3e600e |
hex | 1d4e3eb9a482b |
515550352132139 has 2 divisors, whose sum is σ = 515550352132140. Its totient is φ = 515550352132138.
The previous prime is 515550352132117. The next prime is 515550352132171. The reversal of 515550352132139 is 931231253055515.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-515550352132139 is a prime.
It is not a weakly prime, because it can be changed into another prime (515550382132139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257775176066069 + 257775176066070.
It is an arithmetic number, because the mean of its divisors is an integer number (257775176066070).
Almost surely, 2515550352132139 is an apocalyptic number.
515550352132139 is a deficient number, since it is larger than the sum of its proper divisors (1).
515550352132139 is an equidigital number, since it uses as much as digits as its factorization.
515550352132139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3037500, while the sum is 50.
The spelling of 515550352132139 in words is "five hundred fifteen trillion, five hundred fifty billion, three hundred fifty-two million, one hundred thirty-two thousand, one hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •