Base | Representation |
---|---|
bin | 10111011110011000101000… |
… | …11111111000100010111001 |
3 | 20202202222020222112112000221 |
4 | 23233030110133320202321 |
5 | 23231231421243124032 |
6 | 301442340530300041 |
7 | 13605351163530322 |
oct | 1357142437704271 |
9 | 222688228475027 |
10 | 51621555833017 |
11 | 154a2640550a05 |
12 | 595872a727621 |
13 | 22a5b794642a1 |
14 | ca66d4a95449 |
15 | 5e7bdd887597 |
hex | 2ef3147f88b9 |
51621555833017 has 2 divisors, whose sum is σ = 51621555833018. Its totient is φ = 51621555833016.
The previous prime is 51621555832967. The next prime is 51621555833027. The reversal of 51621555833017 is 71033855512615.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50660742228496 + 960813604521 = 7117636^2 + 980211^2 .
It is a cyclic number.
It is not a de Polignac number, because 51621555833017 - 235 = 51587196094649 is a prime.
It is not a weakly prime, because it can be changed into another prime (51621555833027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25810777916508 + 25810777916509.
It is an arithmetic number, because the mean of its divisors is an integer number (25810777916509).
Almost surely, 251621555833017 is an apocalyptic number.
It is an amenable number.
51621555833017 is a deficient number, since it is larger than the sum of its proper divisors (1).
51621555833017 is an equidigital number, since it uses as much as digits as its factorization.
51621555833017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780000, while the sum is 52.
The spelling of 51621555833017 in words is "fifty-one trillion, six hundred twenty-one billion, five hundred fifty-five million, eight hundred thirty-three thousand, seventeen".
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