Base | Representation |
---|---|
bin | 111010101100010000000110… |
… | …1111100110101011001000101 |
3 | 2111200220112011201001011022112 |
4 | 1311120200031330311121011 |
5 | 1020131311330033432331 |
6 | 5025552225003510405 |
7 | 213512133450101120 |
oct | 16530401574653105 |
9 | 2450815151034275 |
10 | 516255303030341 |
11 | 13a54970a8a3696 |
12 | 49a998a0528405 |
13 | 1920a8877b8954 |
14 | 916ac661ad3b7 |
15 | 3ea3eb9e5632b |
hex | 1d5880df35645 |
516255303030341 has 16 divisors (see below), whose sum is σ = 621221465088000. Its totient is φ = 419105176137648.
The previous prime is 516255303030329. The next prime is 516255303030343. The reversal of 516255303030341 is 143030303552615.
It is a de Polignac number, because none of the positive numbers 2k-516255303030341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (516255303030343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 507158141 + ... + 508175058.
It is an arithmetic number, because the mean of its divisors is an integer number (38826341568000).
Almost surely, 2516255303030341 is an apocalyptic number.
It is an amenable number.
516255303030341 is a deficient number, since it is larger than the sum of its proper divisors (104966162057659).
516255303030341 is a wasteful number, since it uses less digits than its factorization.
516255303030341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1015337048.
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 516255303030341 its reverse (143030303552615), we get a palindrome (659285606582956).
The spelling of 516255303030341 in words is "five hundred sixteen trillion, two hundred fifty-five billion, three hundred three million, thirty thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 1.018 sec. • engine limits •