Base | Representation |
---|---|
bin | 111010101110111010100110… |
… | …0111000101110010000011011 |
3 | 2111202012112012210200002012112 |
4 | 1311131311030320232100123 |
5 | 1020203311142332343212 |
6 | 5030432335315502535 |
7 | 213550444445464316 |
oct | 16535651470562033 |
9 | 2452175183602175 |
10 | 516621431137307 |
11 | 13a67aa11647461 |
12 | 49b3883bbb7a4b |
13 | 19236265845422 |
14 | 91808799dd97d |
15 | 3ead797d58422 |
hex | 1d5dd4ce2e41b |
516621431137307 has 24 divisors (see below), whose sum is σ = 540451294812000. Its totient is φ = 493780063488768.
The previous prime is 516621431137241. The next prime is 516621431137319. The reversal of 516621431137307 is 703731134126615.
It is not a de Polignac number, because 516621431137307 - 222 = 516621426943003 is a prime.
It is a super-2 number, since 2×5166214311373072 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (516621431137337) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 97992194 + ... + 103129592.
It is an arithmetic number, because the mean of its divisors is an integer number (22518803950500).
Almost surely, 2516621431137307 is an apocalyptic number.
516621431137307 is a deficient number, since it is larger than the sum of its proper divisors (23829863674693).
516621431137307 is a wasteful number, since it uses less digits than its factorization.
516621431137307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5138663 (or 5138634 counting only the distinct ones).
The product of its (nonzero) digits is 1905120, while the sum is 50.
The spelling of 516621431137307 in words is "five hundred sixteen trillion, six hundred twenty-one billion, four hundred thirty-one million, one hundred thirty-seven thousand, three hundred seven".
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