Base | Representation |
---|---|
bin | 10111011111100111111000… |
… | …10110110000101100010011 |
3 | 20202221001001222202120100112 |
4 | 23233303330112300230103 |
5 | 23232431034204230311 |
6 | 301514054325311535 |
7 | 13611415400102501 |
oct | 1357637426605423 |
9 | 222831058676315 |
10 | 51664100461331 |
11 | 15509692914956 |
12 | 5964a228655ab |
13 | 22a9b99770377 |
14 | ca87ad1ad671 |
15 | 5e8d7d96328b |
hex | 2efcfc5b0b13 |
51664100461331 has 4 divisors (see below), whose sum is σ = 52638894809712. Its totient is φ = 50689306112952.
The previous prime is 51664100461307. The next prime is 51664100461333. The reversal of 51664100461331 is 13316400146615.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51664100461331 is a prime.
It is a super-2 number, since 2×516641004613312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51664100461333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 487397174111 + ... + 487397174216.
It is an arithmetic number, because the mean of its divisors is an integer number (13159723702428).
Almost surely, 251664100461331 is an apocalyptic number.
51664100461331 is a deficient number, since it is larger than the sum of its proper divisors (974794348381).
51664100461331 is an equidigital number, since it uses as much as digits as its factorization.
51664100461331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 974794348380.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 51664100461331 in words is "fifty-one trillion, six hundred sixty-four billion, one hundred million, four hundred sixty-one thousand, three hundred thirty-one".
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