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517243706330147 is a prime number
BaseRepresentation
bin111010110011011100010111…
…1011000001100110000100011
32111211102000102020020011202222
41311212320233120030300203
51020244010102310031042
65032030251152501255
7213643424141400446
oct16546705730146043
92454360366204688
10517243706330147
1113a89a907787035
124a01936684a82b
131927cb453481c4
1491a2a2c3bb65d
153ebea685632d2
hex1d66e2f60cc23

517243706330147 has 2 divisors, whose sum is σ = 517243706330148. Its totient is φ = 517243706330146.

The previous prime is 517243706330123. The next prime is 517243706330201. The reversal of 517243706330147 is 741033607342715.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 517243706330147 - 218 = 517243706068003 is a prime.

It is a super-2 number, since 2×5172437063301472 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (517243786330147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258621853165073 + 258621853165074.

It is an arithmetic number, because the mean of its divisors is an integer number (258621853165074).

Almost surely, 2517243706330147 is an apocalyptic number.

517243706330147 is a deficient number, since it is larger than the sum of its proper divisors (1).

517243706330147 is an equidigital number, since it uses as much as digits as its factorization.

517243706330147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8890560, while the sum is 53.

The spelling of 517243706330147 in words is "five hundred seventeen trillion, two hundred forty-three billion, seven hundred six million, three hundred thirty thousand, one hundred forty-seven".