Base | Representation |
---|---|
bin | 110000010100010000… |
… | …100001110101111001 |
3 | 11221220120101220001202 |
4 | 300110100201311321 |
5 | 1322222122003133 |
6 | 35455541223545 |
7 | 3514423226153 |
oct | 602420416571 |
9 | 157816356052 |
10 | 51879484793 |
11 | 20002686874 |
12 | a07a401bb5 |
13 | 4b7a26c7c6 |
14 | 27221b7ad3 |
15 | 153989e2e8 |
hex | c14421d79 |
51879484793 has 2 divisors, whose sum is σ = 51879484794. Its totient is φ = 51879484792.
The previous prime is 51879484711. The next prime is 51879484801. The reversal of 51879484793 is 39748497815.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45741232384 + 6138252409 = 213872^2 + 78347^2 .
It is a cyclic number.
It is not a de Polignac number, because 51879484793 - 218 = 51879222649 is a prime.
It is not a weakly prime, because it can be changed into another prime (51879484703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25939742396 + 25939742397.
It is an arithmetic number, because the mean of its divisors is an integer number (25939742397).
Almost surely, 251879484793 is an apocalyptic number.
It is an amenable number.
51879484793 is a deficient number, since it is larger than the sum of its proper divisors (1).
51879484793 is an equidigital number, since it uses as much as digits as its factorization.
51879484793 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 60963840, while the sum is 65.
The spelling of 51879484793 in words is "fifty-one billion, eight hundred seventy-nine million, four hundred eighty-four thousand, seven hundred ninety-three".
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