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52015464433 = 261711987523
BaseRepresentation
bin110000011100010111…
…001111111111110001
311222021001021101001201
4300130113033333301
51323011424330213
635521235531201
73520664103232
oct603427177761
9158231241051
1052015464433
1120072412339
12a0b7a59b01
134b9c49cc2a
142736293089
1515467ae6dd
hexc1c5cfff1

52015464433 has 4 divisors (see below), whose sum is σ = 52017478128. Its totient is φ = 52013450740.

The previous prime is 52015464377. The next prime is 52015464461. The reversal of 52015464433 is 33446451025.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52015464433 - 217 = 52015333361 is a prime.

It is a super-2 number, since 2×520154644332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52015464392 and 52015464401.

It is not an unprimeable number, because it can be changed into a prime (52015464463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 967591 + ... + 1019932.

It is an arithmetic number, because the mean of its divisors is an integer number (13004369532).

Almost surely, 252015464433 is an apocalyptic number.

It is an amenable number.

52015464433 is a deficient number, since it is larger than the sum of its proper divisors (2013695).

52015464433 is a wasteful number, since it uses less digits than its factorization.

52015464433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2013694.

The product of its (nonzero) digits is 172800, while the sum is 37.

The spelling of 52015464433 in words is "fifty-two billion, fifteen million, four hundred sixty-four thousand, four hundred thirty-three".

Divisors: 1 26171 1987523 52015464433