Base | Representation |
---|---|
bin | 10111101011000000100110… |
… | …11110001101100001001001 |
3 | 20211022102220110202022100102 |
4 | 23311200103132031201021 |
5 | 23310333304030024223 |
6 | 302413515535015145 |
7 | 13651605420013664 |
oct | 1365402336154111 |
9 | 224272813668312 |
10 | 52055330314313 |
11 | 1564a5a5978a67 |
12 | 5a0880896a4b5 |
13 | 2307a481387b1 |
14 | cbd6c46b06db |
15 | 60412a434928 |
hex | 2f581378d849 |
52055330314313 has 4 divisors (see below), whose sum is σ = 52055367322128. Its totient is φ = 52055293306500.
The previous prime is 52055330314301. The next prime is 52055330314327. The reversal of 52055330314313 is 31341303355025.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 52055330314313 - 210 = 52055330313289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52055330314363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16307063 + ... + 19236188.
It is an arithmetic number, because the mean of its divisors is an integer number (13013841830532).
Almost surely, 252055330314313 is an apocalyptic number.
It is an amenable number.
52055330314313 is a deficient number, since it is larger than the sum of its proper divisors (37007815).
52055330314313 is a wasteful number, since it uses less digits than its factorization.
52055330314313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37007814.
The product of its (nonzero) digits is 243000, while the sum is 38.
Adding to 52055330314313 its reverse (31341303355025), we get a palindrome (83396633669338).
The spelling of 52055330314313 in words is "fifty-two trillion, fifty-five billion, three hundred thirty million, three hundred fourteen thousand, three hundred thirteen".
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