Base | Representation |
---|---|
bin | 111011001011100010010111… |
… | …1110100011101010001010111 |
3 | 2112021010120210021201000200021 |
4 | 1312113010233310131101113 |
5 | 1021212233403140214111 |
6 | 5043043421005530011 |
7 | 214434603324202315 |
oct | 16627045764352127 |
9 | 2467116707630607 |
10 | 520555133523031 |
11 | 140957213036172 |
12 | 4a4730a4b73907 |
13 | 194601a5273ca9 |
14 | 9279007d290b5 |
15 | 402ac7878ad71 |
hex | 1d9712fd1d457 |
520555133523031 has 16 divisors (see below), whose sum is σ = 523995984838656. Its totient is φ = 517121784000000.
The previous prime is 520555133522857. The next prime is 520555133523041. The reversal of 520555133523031 is 130325331555025.
It is a cyclic number.
It is not a de Polignac number, because 520555133523031 - 219 = 520555132998743 is a prime.
It is a super-2 number, since 2×5205551335230312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (520555133523041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5921343966 + ... + 5921431876.
It is an arithmetic number, because the mean of its divisors is an integer number (32749749052416).
Almost surely, 2520555133523031 is an apocalyptic number.
520555133523031 is a deficient number, since it is larger than the sum of its proper divisors (3440851315625).
520555133523031 is a wasteful number, since it uses less digits than its factorization.
520555133523031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130134.
The product of its (nonzero) digits is 1012500, while the sum is 43.
The spelling of 520555133523031 in words is "five hundred twenty trillion, five hundred fifty-five billion, one hundred thirty-three million, five hundred twenty-three thousand, thirty-one".
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