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5210433001330 = 253311574148943
BaseRepresentation
bin100101111010010011000…
…0000100001011101110010
3200110010001000221012012021
41023310212000201131302
51140331431322020310
615025350114022054
71045304246521504
oct113644600413562
920403030835167
105210433001330
111729806659007
1270199757792a
132ba4599c82bb
14140287301d74
1590806a855da
hex4bd26021772

5210433001330 has 16 divisors (see below), whose sum is σ = 9407114089344. Its totient is φ = 2077876603440.

The previous prime is 5210433001327. The next prime is 5210433001373. The reversal of 5210433001330 is 331003340125.

It is a super-2 number, since 2×52104330013302 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5210433001295 and 5210433001304.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 787071162 + ... + 787077781.

It is an arithmetic number, because the mean of its divisors is an integer number (587944630584).

Almost surely, 25210433001330 is an apocalyptic number.

5210433001330 is a deficient number, since it is larger than the sum of its proper divisors (4196681088014).

5210433001330 is a wasteful number, since it uses less digits than its factorization.

5210433001330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1574149281.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 5210433001330 its reverse (331003340125), we get a palindrome (5541436341455).

The spelling of 5210433001330 in words is "five trillion, two hundred ten billion, four hundred thirty-three million, one thousand, three hundred thirty".

Divisors: 1 2 5 10 331 662 1655 3310 1574148943 3148297886 7870744715 15741489430 521043300133 1042086600266 2605216500665 5210433001330