Base | Representation |
---|---|
bin | 100101111010101011011… |
… | …1100100010100110101011 |
3 | 200110012011020212022220001 |
4 | 1023311112330202212223 |
5 | 1140340122013303003 |
6 | 15030003403443431 |
7 | 1045333506324253 |
oct | 113652674424653 |
9 | 20405136768801 |
10 | 5211254041003 |
11 | 172a09805a29a |
12 | 701b86526577 |
13 | 2ba55ab368aa |
14 | 140324386963 |
15 | 90853bb661d |
hex | 4bd56f229ab |
5211254041003 has 4 divisors (see below), whose sum is σ = 5390952456240. Its totient is φ = 5031555625768.
The previous prime is 5211254040989. The next prime is 5211254041039. The reversal of 5211254041003 is 3001404521125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5211254041003 - 237 = 5073815087531 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5211254041093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89849207575 + ... + 89849207632.
It is an arithmetic number, because the mean of its divisors is an integer number (1347738114060).
Almost surely, 25211254041003 is an apocalyptic number.
5211254041003 is a deficient number, since it is larger than the sum of its proper divisors (179698415237).
5211254041003 is a wasteful number, since it uses less digits than its factorization.
5211254041003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179698415236.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 5211254041003 its reverse (3001404521125), we get a palindrome (8212658562128).
The spelling of 5211254041003 in words is "five trillion, two hundred eleven billion, two hundred fifty-four million, forty-one thousand, three".
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