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521133144043 = 539832700831
BaseRepresentation
bin1111001010101011111…
…01001011011111101011
31211211010122221122220011
413211111331023133223
532014240041102133
61035223311512351
752436110431241
oct7452575133753
91754118848804
10521133144043
1119101408a3a6
1284bba5286b7
133a1b150c435
141b319bd4791
15d8510d06cd
hex7955f4b7eb

521133144043 has 4 divisors (see below), whose sum is σ = 530965844928. Its totient is φ = 511300443160.

The previous prime is 521133144001. The next prime is 521133144097. The reversal of 521133144043 is 340441331125.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 521133144043 - 213 = 521133135851 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 521133143996 and 521133144014.

It is not an unprimeable number, because it can be changed into a prime (521133148043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4916350363 + ... + 4916350468.

It is an arithmetic number, because the mean of its divisors is an integer number (132741461232).

Almost surely, 2521133144043 is an apocalyptic number.

521133144043 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

521133144043 is a deficient number, since it is larger than the sum of its proper divisors (9832700885).

521133144043 is an equidigital number, since it uses as much as digits as its factorization.

521133144043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9832700884.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 521133144043 its reverse (340441331125), we get a palindrome (861574475168).

The spelling of 521133144043 in words is "five hundred twenty-one billion, one hundred thirty-three million, one hundred forty-four thousand, forty-three".

Divisors: 1 53 9832700831 521133144043