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52116163153 = 299917377847
BaseRepresentation
bin110000100010010111…
…011000101001010001
311222112001202101201221
4300202113120221101
51323213214210103
635535234125041
73523326035425
oct604227305121
9158461671657
1052116163153
112011424081a
12a125720781
134bb72c9782
1427457c6b85
1515505511bd
hexc225d8a51

52116163153 has 4 divisors (see below), whose sum is σ = 52133544000. Its totient is φ = 52098782308.

The previous prime is 52116163147. The next prime is 52116163181. The reversal of 52116163153 is 35136161125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52116163153 - 29 = 52116162641 is a prime.

It is a super-3 number, since 3×521161631533 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52116163553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8685925 + ... + 8691922.

It is an arithmetic number, because the mean of its divisors is an integer number (13033386000).

Almost surely, 252116163153 is an apocalyptic number.

It is an amenable number.

52116163153 is a deficient number, since it is larger than the sum of its proper divisors (17380847).

52116163153 is a wasteful number, since it uses less digits than its factorization.

52116163153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17380846.

The product of its digits is 16200, while the sum is 34.

The spelling of 52116163153 in words is "fifty-two billion, one hundred sixteen million, one hundred sixty-three thousand, one hundred fifty-three".

Divisors: 1 2999 17377847 52116163153