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5212546433 is a prime number
BaseRepresentation
bin1001101101011000…
…10010010110000001
3111110021022210110022
410312230102112001
541133402441213
62221122543225
7243112625243
oct46654222601
914407283408
105212546433
11223538a316
121015807b15
13650bb9803
143763cc093
1520793d308
hex136b12581

5212546433 has 2 divisors, whose sum is σ = 5212546434. Its totient is φ = 5212546432.

The previous prime is 5212546363. The next prime is 5212546447. The reversal of 5212546433 is 3346452125.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4051577104 + 1160969329 = 63652^2 + 34073^2 .

It is a cyclic number.

It is not a de Polignac number, because 5212546433 - 28 = 5212546177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5212546393 and 5212546402.

It is not a weakly prime, because it can be changed into another prime (5212546453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2606273216 + 2606273217.

It is an arithmetic number, because the mean of its divisors is an integer number (2606273217).

Almost surely, 25212546433 is an apocalyptic number.

It is an amenable number.

5212546433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5212546433 is an equidigital number, since it uses as much as digits as its factorization.

5212546433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 86400, while the sum is 35.

The square root of 5212546433 is about 72197.9669589110. The cubic root of 5212546433 is about 1733.8704519310.

Adding to 5212546433 its reverse (3346452125), we get a palindrome (8558998558).

The spelling of 5212546433 in words is "five billion, two hundred twelve million, five hundred forty-six thousand, four hundred thirty-three".