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52132035433 is a prime number
BaseRepresentation
bin110000100011010011…
…111011101101101001
311222120011121210102011
4300203103323231221
51323231300113213
635541002235521
73523610663332
oct604323735551
9158504553364
1052132035433
11201221a1905
12a12aab5ba1
134bba69615a
142747959289
151551b3903d
hexc234fbb69

52132035433 has 2 divisors, whose sum is σ = 52132035434. Its totient is φ = 52132035432.

The previous prime is 52132035409. The next prime is 52132035437. The reversal of 52132035433 is 33453023125.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46099095849 + 6032939584 = 214707^2 + 77672^2 .

It is a cyclic number.

It is not a de Polignac number, because 52132035433 - 233 = 43542100841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52132035395 and 52132035404.

It is not a weakly prime, because it can be changed into another prime (52132035437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26066017716 + 26066017717.

It is an arithmetic number, because the mean of its divisors is an integer number (26066017717).

Almost surely, 252132035433 is an apocalyptic number.

It is an amenable number.

52132035433 is a deficient number, since it is larger than the sum of its proper divisors (1).

52132035433 is an equidigital number, since it uses as much as digits as its factorization.

52132035433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 52132035433 its reverse (33453023125), we get a palindrome (85585058558).

The spelling of 52132035433 in words is "fifty-two billion, one hundred thirty-two million, thirty-five thousand, four hundred thirty-three".