Base | Representation |
---|---|
bin | 100101111011101011101… |
… | …1101101001110111100001 |
3 | 200110101201112001211001112 |
4 | 1023313113131221313201 |
5 | 1140404031003031103 |
6 | 15031001345513105 |
7 | 1045441110401153 |
oct | 113672735516741 |
9 | 20411645054045 |
10 | 5213410205153 |
11 | 172aaa4169337 |
12 | 702488642795 |
13 | 2ba81275a777 |
14 | 14048a892ad3 |
15 | 9092d124cd8 |
hex | 4bdd7769de1 |
5213410205153 has 2 divisors, whose sum is σ = 5213410205154. Its totient is φ = 5213410205152.
The previous prime is 5213410205149. The next prime is 5213410205191. The reversal of 5213410205153 is 3515020143125.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3004179828049 + 2209230377104 = 1733257^2 + 1486348^2 .
It is a cyclic number.
It is not a de Polignac number, because 5213410205153 - 22 = 5213410205149 is a prime.
It is not a weakly prime, because it can be changed into another prime (5213410205053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2606705102576 + 2606705102577.
It is an arithmetic number, because the mean of its divisors is an integer number (2606705102577).
Almost surely, 25213410205153 is an apocalyptic number.
It is an amenable number.
5213410205153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5213410205153 is an equidigital number, since it uses as much as digits as its factorization.
5213410205153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 5213410205153 its reverse (3515020143125), we get a palindrome (8728430348278).
The spelling of 5213410205153 in words is "five trillion, two hundred thirteen billion, four hundred ten million, two hundred five thousand, one hundred fifty-three".
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