Base | Representation |
---|---|
bin | 10111101101010011101000… |
… | …11011010000001111101011 |
3 | 20211120222122122210220102121 |
4 | 23312221310123100033223 |
5 | 23313131434140342311 |
6 | 302514052404012111 |
7 | 13660401502116430 |
oct | 1366516433201753 |
9 | 224528578726377 |
10 | 52134266340331 |
11 | 156800222366aa |
12 | 5a1bb78391037 |
13 | 23123179c46b6 |
14 | cc3452007b87 |
15 | 6061ea2d6b71 |
hex | 2f6a746d03eb |
52134266340331 has 4 divisors (see below), whose sum is σ = 59582018674672. Its totient is φ = 44686514005992.
The previous prime is 52134266340319. The next prime is 52134266340337. The reversal of 52134266340331 is 13304366243125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52134266340331 - 213 = 52134266332139 is a prime.
It is a super-2 number, since 2×521342663403312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52134266340337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3723876167160 + ... + 3723876167173.
It is an arithmetic number, because the mean of its divisors is an integer number (14895504668668).
Almost surely, 252134266340331 is an apocalyptic number.
52134266340331 is a deficient number, since it is larger than the sum of its proper divisors (7447752334341).
52134266340331 is an equidigital number, since it uses as much as digits as its factorization.
52134266340331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7447752334340.
The product of its (nonzero) digits is 933120, while the sum is 43.
The spelling of 52134266340331 in words is "fifty-two trillion, one hundred thirty-four billion, two hundred sixty-six million, three hundred forty thousand, three hundred thirty-one".
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