5213441113 has 4 divisors (see below), whose sum is σ = 5324365440. Its totient is φ = 5102516788.

The previous prime is 5213441083. The next prime is 5213441147. The reversal of 5213441113 is 3111443125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5213441113 - 2²⁵ = 5179886681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5213441413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55462093 + ... + 55462186.

It is an arithmetic number, because the mean of its divisors is an integer number (1331091360).

Almost surely, 2^5213441113 is an apocalyptic number.

It is an amenable number.

5213441113 is a deficient number, since it is larger than the sum of its proper divisors (110924327).

5213441113 is a wasteful number, since it uses less digits than its factorization.

5213441113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110924326.

The product of its digits is 1440, while the sum is 25.

The square root of 5213441113 is about 72204.1627124088. The cubic root of 5213441113 is about 1733.9696466011.

Adding to 5213441113 its reverse (3111443125), we get a palindrome (8324884238).

The spelling of 5213441113 in words is "five billion, two hundred thirteen million, four hundred forty-one thousand, one hundred thirteen".