Base | Representation |
---|---|
bin | 110000100011110010… |
… | …111000111010001011 |
3 | 11222120201220002001220 |
4 | 300203302320322023 |
5 | 1323240334303121 |
6 | 35541452213123 |
7 | 3524036652216 |
oct | 604362707213 |
9 | 158521802056 |
10 | 52140150411 |
11 | 201268347a8 |
12 | a13176a1a3 |
13 | 4bbc277a0b |
14 | 2748a6c77d |
15 | 15526dd6c6 |
hex | c23cb8e8b |
52140150411 has 4 divisors (see below), whose sum is σ = 69520200552. Its totient is φ = 34760100272.
The previous prime is 52140150401. The next prime is 52140150427. The reversal of 52140150411 is 11405104125.
52140150411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52140150411 - 215 = 52140117643 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52140150401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8690025066 + ... + 8690025071.
It is an arithmetic number, because the mean of its divisors is an integer number (17380050138).
Almost surely, 252140150411 is an apocalyptic number.
52140150411 is a deficient number, since it is larger than the sum of its proper divisors (17380050141).
52140150411 is a wasteful number, since it uses less digits than its factorization.
52140150411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17380050140.
The product of its (nonzero) digits is 800, while the sum is 24.
Adding to 52140150411 its reverse (11405104125), we get a palindrome (63545254536).
The spelling of 52140150411 in words is "fifty-two billion, one hundred forty million, one hundred fifty thousand, four hundred eleven".
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