Base | Representation |
---|---|
bin | 10111101101100010011110… |
… | …10011100110010111110011 |
3 | 20211121202012220110010111222 |
4 | 23312301033103212113303 |
5 | 23313244243234331121 |
6 | 302521451132055255 |
7 | 13661103104006441 |
oct | 1366611723462763 |
9 | 224552186403458 |
10 | 52142233511411 |
11 | 1568344052120a |
12 | 5a2162060452b |
13 | 2312cb74b2004 |
14 | cc39aa1a7b91 |
15 | 60651499a0ab |
hex | 2f6c4f4e65f3 |
52142233511411 has 8 divisors (see below), whose sum is σ = 52540573747200. Its totient is φ = 51743897941320.
The previous prime is 52142233511399. The next prime is 52142233511447. The reversal of 52142233511411 is 11411533224125.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 52142233511411 - 222 = 52142229317107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52142233511111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23208350 + ... + 25355708.
It is an arithmetic number, because the mean of its divisors is an integer number (6567571718400).
Almost surely, 252142233511411 is an apocalyptic number.
52142233511411 is a deficient number, since it is larger than the sum of its proper divisors (398340235789).
52142233511411 is a wasteful number, since it uses less digits than its factorization.
52142233511411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2332849.
The product of its digits is 28800, while the sum is 35.
Adding to 52142233511411 its reverse (11411533224125), we get a palindrome (63553766735536).
The spelling of 52142233511411 in words is "fifty-two trillion, one hundred forty-two billion, two hundred thirty-three million, five hundred eleven thousand, four hundred eleven".
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