Base | Representation |
---|---|
bin | 110000100011111110… |
… | …010011110110001011 |
3 | 11222120221112011221211 |
4 | 300203332103312023 |
5 | 1323242121104311 |
6 | 35542040313551 |
7 | 3524104261645 |
oct | 604376236613 |
9 | 158527464854 |
10 | 52143144331 |
11 | 2012849a113 |
12 | a1327728b7 |
13 | 4bbca85675 |
14 | 274920b895 |
15 | 1552ad0821 |
hex | c23f93d8b |
52143144331 has 2 divisors, whose sum is σ = 52143144332. Its totient is φ = 52143144330.
The previous prime is 52143144289. The next prime is 52143144371. The reversal of 52143144331 is 13344134125.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52143144331 - 27 = 52143144203 is a prime.
It is a super-2 number, since 2×521431443312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52143144293 and 52143144302.
It is not a weakly prime, because it can be changed into another prime (52143144371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26071572165 + 26071572166.
It is an arithmetic number, because the mean of its divisors is an integer number (26071572166).
Almost surely, 252143144331 is an apocalyptic number.
52143144331 is a deficient number, since it is larger than the sum of its proper divisors (1).
52143144331 is an equidigital number, since it uses as much as digits as its factorization.
52143144331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17280, while the sum is 31.
Adding to 52143144331 its reverse (13344134125), we get a palindrome (65487278456).
The spelling of 52143144331 in words is "fifty-two billion, one hundred forty-three million, one hundred forty-four thousand, three hundred thirty-one".
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