Base | Representation |
---|---|
bin | 100101111100001001100… |
… | …1001111101000010011001 |
3 | 200110111022022111200201011 |
4 | 1023320103021331002121 |
5 | 1140413103342030003 |
6 | 15031245002453521 |
7 | 1045504660626532 |
oct | 113702311750231 |
9 | 20414268450634 |
10 | 5214411673753 |
11 | 17304684a5537 |
12 | 702707b042a1 |
13 | 2ba942090239 |
14 | 1405438a3689 |
15 | 9098aee646d |
hex | 4be1327d099 |
5214411673753 has 4 divisors (see below), whose sum is σ = 5214917790208. Its totient is φ = 5213905557300.
The previous prime is 5214411673747. The next prime is 5214411673777. The reversal of 5214411673753 is 3573761144125.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5214411673753 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5214411673697 and 5214411673706.
It is not an unprimeable number, because it can be changed into a prime (5214411673703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253042773 + ... + 253063378.
It is an arithmetic number, because the mean of its divisors is an integer number (1303729447552).
Almost surely, 25214411673753 is an apocalyptic number.
It is an amenable number.
5214411673753 is a deficient number, since it is larger than the sum of its proper divisors (506116455).
5214411673753 is a wasteful number, since it uses less digits than its factorization.
5214411673753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 506116454.
The product of its digits is 2116800, while the sum is 49.
The spelling of 5214411673753 in words is "five trillion, two hundred fourteen billion, four hundred eleven million, six hundred seventy-three thousand, seven hundred fifty-three".
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