Base | Representation |
---|---|
bin | 100101111100110000011… |
… | …0011011100100000101011 |
3 | 200110121200002210211221210 |
4 | 1023321200303130200223 |
5 | 1140423240341134303 |
6 | 15032022140404203 |
7 | 1045552156606263 |
oct | 113714063344053 |
9 | 20417602724853 |
10 | 5215714396203 |
11 | 1730a76892163 |
12 | 702a10246663 |
13 | 2baabbc3c41c |
14 | 1406288d27a3 |
15 | 90a15573203 |
hex | 4be60cdc82b |
5215714396203 has 6 divisors (see below), whose sum is σ = 6954291135804. Its totient is φ = 3477140293704.
The previous prime is 5215714396201. The next prime is 5215714396313. The reversal of 5215714396203 is 3026934175125.
5215714396203 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5215714396203 - 21 = 5215714396201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5215714396201) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3296373 + ... + 4614921.
It is an arithmetic number, because the mean of its divisors is an integer number (1159048522634).
Almost surely, 25215714396203 is an apocalyptic number.
5215714396203 is a deficient number, since it is larger than the sum of its proper divisors (1738576739601).
5215714396203 is an frugal number, since it uses more digits than its factorization.
5215714396203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2637101 (or 1318552 counting only the distinct ones).
The product of its (nonzero) digits is 1360800, while the sum is 48.
Multiplying 5215714396203 by its sum of digits (48), we get a square (250354291017744 = 158225882).
The spelling of 5215714396203 in words is "five trillion, two hundred fifteen billion, seven hundred fourteen million, three hundred ninety-six thousand, two hundred three".
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