Base | Representation |
---|---|
bin | 10111101110011010100101… |
… | …00110001111010010101011 |
3 | 20211201121222000112002202011 |
4 | 23313031102212033102223 |
5 | 23314242434444002311 |
6 | 302543352012020351 |
7 | 13663220361462301 |
oct | 1367152246172253 |
9 | 224647860462664 |
10 | 52172353500331 |
11 | 15695197469739 |
12 | 5a274277616b7 |
13 | 2315aa7698c6c |
14 | cc5226528271 |
15 | 6071c8dc6321 |
hex | 2f735298f4ab |
52172353500331 has 2 divisors, whose sum is σ = 52172353500332. Its totient is φ = 52172353500330.
The previous prime is 52172353500277. The next prime is 52172353500359. The reversal of 52172353500331 is 13300535327125.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52172353500331 - 235 = 52137993761963 is a prime.
It is a super-2 number, since 2×521723535003312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52172353500031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26086176750165 + 26086176750166.
It is an arithmetic number, because the mean of its divisors is an integer number (26086176750166).
Almost surely, 252172353500331 is an apocalyptic number.
52172353500331 is a deficient number, since it is larger than the sum of its proper divisors (1).
52172353500331 is an equidigital number, since it uses as much as digits as its factorization.
52172353500331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 283500, while the sum is 40.
Adding to 52172353500331 its reverse (13300535327125), we get a palindrome (65472888827456).
The spelling of 52172353500331 in words is "fifty-two trillion, one hundred seventy-two billion, three hundred fifty-three million, five hundred thousand, three hundred thirty-one".
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