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52213115042993 is a prime number
BaseRepresentation
bin10111101111100110100000…
…01011001011110010110001
320211212112011202120000101102
423313303100023023302301
523320424424422333433
6303014212433214145
713666162444045142
oct1367632013136261
9224775152500342
1052213115042993
1115700504280a83
125a33302701355
1323198a2457a88
14cc71b1ccdac9
156082b268a4e8
hex2f7cd02cbcb1

52213115042993 has 2 divisors, whose sum is σ = 52213115042994. Its totient is φ = 52213115042992.

The previous prime is 52213115042983. The next prime is 52213115043017. The reversal of 52213115042993 is 39924051131225.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27967417826929 + 24245697216064 = 5288423^2 + 4923992^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52213115042993 is a prime.

It is not a weakly prime, because it can be changed into another prime (52213115042903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26106557521496 + 26106557521497.

It is an arithmetic number, because the mean of its divisors is an integer number (26106557521497).

Almost surely, 252213115042993 is an apocalyptic number.

It is an amenable number.

52213115042993 is a deficient number, since it is larger than the sum of its proper divisors (1).

52213115042993 is an equidigital number, since it uses as much as digits as its factorization.

52213115042993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 583200, while the sum is 47.

The spelling of 52213115042993 in words is "fifty-two trillion, two hundred thirteen billion, one hundred fifteen million, forty-two thousand, nine hundred ninety-three".