Base | Representation |
---|---|
bin | 100101111111110011001… |
… | …1011000010011011000011 |
3 | 200111020112122210102110201 |
4 | 1023333212123002123003 |
5 | 1141030132241042011 |
6 | 15035022525110031 |
7 | 1046203152021154 |
oct | 113774633023303 |
9 | 20436478712421 |
10 | 5222251112131 |
11 | 1733820677629 |
12 | 7041353b8317 |
13 | 2bb5c1277081 |
14 | 140a88ad392b |
15 | 90c99377cc1 |
hex | 4bfe66c26c3 |
5222251112131 has 2 divisors, whose sum is σ = 5222251112132. Its totient is φ = 5222251112130.
The previous prime is 5222251112047. The next prime is 5222251112213. The reversal of 5222251112131 is 1312111522225.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5222251112131 - 227 = 5222116894403 is a prime.
It is a super-2 number, since 2×52222511121312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5222251112131.
It is not a weakly prime, because it can be changed into another prime (5222251122131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2611125556065 + 2611125556066.
It is an arithmetic number, because the mean of its divisors is an integer number (2611125556066).
Almost surely, 25222251112131 is an apocalyptic number.
5222251112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5222251112131 is an equidigital number, since it uses as much as digits as its factorization.
5222251112131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2400, while the sum is 28.
Adding to 5222251112131 its reverse (1312111522225), we get a palindrome (6534362634356).
The spelling of 5222251112131 in words is "five trillion, two hundred twenty-two billion, two hundred fifty-one million, one hundred twelve thousand, one hundred thirty-one".
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