Base | Representation |
---|---|
bin | 10111110000011101001001… |
… | …10000101011000110011001 |
3 | 20211222022220021011121020112 |
4 | 23320032210300223012121 |
5 | 23321420020032202441 |
6 | 303035503442134105 |
7 | 14001251435251331 |
oct | 1370164460530631 |
9 | 224868807147215 |
10 | 52242451444121 |
11 | 15711998978394 |
12 | 5a38b2b351335 |
13 | 231c5991b7203 |
14 | cc87961580c1 |
15 | 608e2cdd24eb |
hex | 2f83a4c2b199 |
52242451444121 has 2 divisors, whose sum is σ = 52242451444122. Its totient is φ = 52242451444120.
The previous prime is 52242451444049. The next prime is 52242451444163. The reversal of 52242451444121 is 12144415424225.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38975111430025 + 13267340014096 = 6243005^2 + 3642436^2 .
It is a cyclic number.
It is not a de Polignac number, because 52242451444121 - 238 = 51967573537177 is a prime.
It is not a weakly prime, because it can be changed into another prime (52242451440121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26121225722060 + 26121225722061.
It is an arithmetic number, because the mean of its divisors is an integer number (26121225722061).
Almost surely, 252242451444121 is an apocalyptic number.
It is an amenable number.
52242451444121 is a deficient number, since it is larger than the sum of its proper divisors (1).
52242451444121 is an equidigital number, since it uses as much as digits as its factorization.
52242451444121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 409600, while the sum is 41.
Adding to 52242451444121 its reverse (12144415424225), we get a palindrome (64386866868346).
The spelling of 52242451444121 in words is "fifty-two trillion, two hundred forty-two billion, four hundred fifty-one million, four hundred forty-four thousand, one hundred twenty-one".
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