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52251314771 = 487710713823
BaseRepresentation
bin110000101010011010…
…111100101001010011
311222212111001210220102
4300222122330221103
51324002314033041
640000503003015
73526556563445
oct605232745123
9158774053812
1052251314771
1120183561177
12a162a3946b
134c092ca046
142759728495
15155c34b09b
hexc2a6bca53

52251314771 has 4 divisors (see below), whose sum is σ = 52262033472. Its totient is φ = 52240596072.

The previous prime is 52251314741. The next prime is 52251314807. The reversal of 52251314771 is 17741315225.

52251314771 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52251314771 - 214 = 52251298387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52251314741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5352035 + ... + 5361788.

It is an arithmetic number, because the mean of its divisors is an integer number (13065508368).

Almost surely, 252251314771 is an apocalyptic number.

52251314771 is a deficient number, since it is larger than the sum of its proper divisors (10718701).

52251314771 is a wasteful number, since it uses less digits than its factorization.

52251314771 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10718700.

The product of its digits is 58800, while the sum is 38.

Adding to 52251314771 its reverse (17741315225), we get a palindrome (69992629996).

The spelling of 52251314771 in words is "fifty-two billion, two hundred fifty-one million, three hundred fourteen thousand, seven hundred seventy-one".

Divisors: 1 4877 10713823 52251314771