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52292917433 is a prime number
BaseRepresentation
bin110000101100111001…
…101001100010111001
311222222101100110000202
4300230321221202321
51324043441324213
640004550411545
73530603315141
oct605471514271
9158871313022
1052292917433
11201a4a96939
12a174960bb5
134c14b051c3
142761077921
151560d17b58
hexc2ce698b9

52292917433 has 2 divisors, whose sum is σ = 52292917434. Its totient is φ = 52292917432.

The previous prime is 52292917423. The next prime is 52292917463. The reversal of 52292917433 is 33471929225.

52292917433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48617163049 + 3675754384 = 220493^2 + 60628^2 .

It is a cyclic number.

It is not a de Polignac number, because 52292917433 - 220 = 52291868857 is a prime.

It is not a weakly prime, because it can be changed into another prime (52292917423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26146458716 + 26146458717.

It is an arithmetic number, because the mean of its divisors is an integer number (26146458717).

Almost surely, 252292917433 is an apocalyptic number.

It is an amenable number.

52292917433 is a deficient number, since it is larger than the sum of its proper divisors (1).

52292917433 is an equidigital number, since it uses as much as digits as its factorization.

52292917433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 816480, while the sum is 47.

The spelling of 52292917433 in words is "fifty-two billion, two hundred ninety-two million, nine hundred seventeen thousand, four hundred thirty-three".