Base | Representation |
---|---|
bin | 110000101100111101… |
… | …110000110001010011 |
3 | 11222222110101012222222 |
4 | 300230331300301103 |
5 | 1324044230324403 |
6 | 40005025451255 |
7 | 3530615425403 |
oct | 605475606123 |
9 | 158873335888 |
10 | 52293995603 |
11 | 201a5662993 |
12 | a1751a0b2b |
13 | 4c150c1b85 |
14 | 2761278803 |
15 | 1560e7c338 |
hex | c2cf70c53 |
52293995603 has 2 divisors, whose sum is σ = 52293995604. Its totient is φ = 52293995602.
The previous prime is 52293995597. The next prime is 52293995711. The reversal of 52293995603 is 30659939225.
52293995603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52293995603 - 222 = 52289801299 is a prime.
It is a super-2 number, since 2×522939956032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52293995903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26146997801 + 26146997802.
It is an arithmetic number, because the mean of its divisors is an integer number (26146997802).
Almost surely, 252293995603 is an apocalyptic number.
52293995603 is a deficient number, since it is larger than the sum of its proper divisors (1).
52293995603 is an equidigital number, since it uses as much as digits as its factorization.
52293995603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3936600, while the sum is 53.
The spelling of 52293995603 in words is "fifty-two billion, two hundred ninety-three million, nine hundred ninety-five thousand, six hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.202 sec. • engine limits •