Base | Representation |
---|---|
bin | 1111001110011010100… |
… | …11010000101100110001 |
3 | 1212000022012120212211121 |
4 | 13213031103100230301 |
5 | 32032340131434413 |
6 | 1040154115342241 |
7 | 52536532466125 |
oct | 7471523205461 |
9 | 1760265525747 |
10 | 523135421233 |
11 | 191951341937 |
12 | 85478bb1981 |
13 | 3a4402a3139 |
14 | 1b469ac3585 |
15 | d91bc92b8d |
hex | 79cd4d0b31 |
523135421233 has 2 divisors, whose sum is σ = 523135421234. Its totient is φ = 523135421232.
The previous prime is 523135421213. The next prime is 523135421269. The reversal of 523135421233 is 332124531325.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 402377086224 + 120758335009 = 634332^2 + 347503^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-523135421233 is a prime.
It is a super-3 number, since 3×5231354212333 (a number of 36 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (523135421213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 261567710616 + 261567710617.
It is an arithmetic number, because the mean of its divisors is an integer number (261567710617).
Almost surely, 2523135421233 is an apocalyptic number.
It is an amenable number.
523135421233 is a deficient number, since it is larger than the sum of its proper divisors (1).
523135421233 is an equidigital number, since it uses as much as digits as its factorization.
523135421233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64800, while the sum is 34.
Adding to 523135421233 its reverse (332124531325), we get a palindrome (855259952558).
The spelling of 523135421233 in words is "five hundred twenty-three billion, one hundred thirty-five million, four hundred twenty-one thousand, two hundred thirty-three".
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