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523304714411131 = 4412311860134497
BaseRepresentation
bin111011011111100010101111…
…1100111001001110001111011
32112121212102221022020100120011
41312333011133213021301323
51022042311023342124011
65052550511134442351
7215140342442135152
oct16677053747116173
92477772838210504
10523304714411131
11141817312839724
124a837b620633b7
13195cc565c415b3
1493321248b2599
1540775534c9621
hex1dbf15f9c9c7b

523304714411131 has 4 divisors (see below), whose sum is σ = 523316574589752. Its totient is φ = 523292854232512.

The previous prime is 523304714411119. The next prime is 523304714411173. The reversal of 523304714411131 is 131114417403325.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 523304714411131 - 25 = 523304714411099 is a prime.

It is a super-2 number, since 2×5233047144111312 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (523304714411111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5930023126 + ... + 5930111371.

It is an arithmetic number, because the mean of its divisors is an integer number (130829143647438).

Almost surely, 2523304714411131 is an apocalyptic number.

523304714411131 is a deficient number, since it is larger than the sum of its proper divisors (11860178621).

523304714411131 is a wasteful number, since it uses less digits than its factorization.

523304714411131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11860178620.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 523304714411131 in words is "five hundred twenty-three trillion, three hundred four billion, seven hundred fourteen million, four hundred eleven thousand, one hundred thirty-one".

Divisors: 1 44123 11860134497 523304714411131