Base | Representation |
---|---|
bin | 111011011111100010101111… |
… | …1100111001001110001111011 |
3 | 2112121212102221022020100120011 |
4 | 1312333011133213021301323 |
5 | 1022042311023342124011 |
6 | 5052550511134442351 |
7 | 215140342442135152 |
oct | 16677053747116173 |
9 | 2477772838210504 |
10 | 523304714411131 |
11 | 141817312839724 |
12 | 4a837b620633b7 |
13 | 195cc565c415b3 |
14 | 93321248b2599 |
15 | 40775534c9621 |
hex | 1dbf15f9c9c7b |
523304714411131 has 4 divisors (see below), whose sum is σ = 523316574589752. Its totient is φ = 523292854232512.
The previous prime is 523304714411119. The next prime is 523304714411173. The reversal of 523304714411131 is 131114417403325.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 523304714411131 - 25 = 523304714411099 is a prime.
It is a super-2 number, since 2×5233047144111312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (523304714411111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5930023126 + ... + 5930111371.
It is an arithmetic number, because the mean of its divisors is an integer number (130829143647438).
Almost surely, 2523304714411131 is an apocalyptic number.
523304714411131 is a deficient number, since it is larger than the sum of its proper divisors (11860178621).
523304714411131 is a wasteful number, since it uses less digits than its factorization.
523304714411131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11860178620.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 523304714411131 in words is "five hundred twenty-three trillion, three hundred four billion, seven hundred fourteen million, four hundred eleven thousand, one hundred thirty-one".
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