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523420313114121 = 31328749131306543
BaseRepresentation
bin111011100000011000100100…
…1110101001101011000001001
32112122021111022120120220121020
41313000301021311031120021
51022101204300124122441
65053115550004103053
7215151604205660643
oct16700611165153011
92478244276526536
10523420313114121
111418613432391a5
124a856443994a89
131960a4293304b7
14933796d483893
15407a56bd8be66
hex1dc0c49d4d609

523420313114121 has 8 divisors (see below), whose sum is σ = 697894281360000. Its totient is φ = 348946610138832.

The previous prime is 523420313114119. The next prime is 523420313114131. The reversal of 523420313114121 is 121411313024325.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 523420313114121 - 21 = 523420313114119 is a prime.

It is not an unprimeable number, because it can be changed into a prime (523420313114131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61667025 + ... + 69639518.

It is an arithmetic number, because the mean of its divisors is an integer number (87236785170000).

Almost surely, 2523420313114121 is an apocalyptic number.

It is an amenable number.

523420313114121 is a deficient number, since it is larger than the sum of its proper divisors (174473968245879).

523420313114121 is a wasteful number, since it uses less digits than its factorization.

523420313114121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132635295.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 523420313114121 its reverse (121411313024325), we get a palindrome (644831626138446).

The spelling of 523420313114121 in words is "five hundred twenty-three trillion, four hundred twenty billion, three hundred thirteen million, one hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3 1328749 3986247 131306543 393919629 174473437704707 523420313114121