Base | Representation |
---|---|
bin | 1001110000011110… |
… | …00000111100101001 |
3 | 111112002000200111212 |
4 | 10320033000330221 |
5 | 41212014134213 |
6 | 2223445402505 |
7 | 243545620121 |
oct | 47017007451 |
9 | 14462020455 |
10 | 5238427433 |
11 | 2248a57078 |
12 | 1022409435 |
13 | 65637ba05 |
14 | 379a07c81 |
15 | 209d519a8 |
hex | 1383c0f29 |
5238427433 has 4 divisors (see below), whose sum is σ = 5514134160. Its totient is φ = 4962720708.
The previous prime is 5238427427. The next prime is 5238427451. The reversal of 5238427433 is 3347248325.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5238427433 - 24 = 5238427417 is a prime.
It is a super-2 number, since 2×52384274332 = 54882243941613938978, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5238427633) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137853335 + ... + 137853372.
It is an arithmetic number, because the mean of its divisors is an integer number (1378533540).
Almost surely, 25238427433 is an apocalyptic number.
It is an amenable number.
5238427433 is a deficient number, since it is larger than the sum of its proper divisors (275706727).
5238427433 is a wasteful number, since it uses less digits than its factorization.
5238427433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275706726.
The product of its digits is 483840, while the sum is 41.
The square root of 5238427433 is about 72376.9813752964. The cubic root of 5238427433 is about 1736.7353495988.
The spelling of 5238427433 in words is "five billion, two hundred thirty-eight million, four hundred twenty-seven thousand, four hundred thirty-three".
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