Base | Representation |
---|---|
bin | 10111110101000100010110… |
… | …01100111011000110000001 |
3 | 20212112110222100122011022110 |
4 | 23322202023030323012001 |
5 | 23332014104211311001 |
6 | 303240354033325533 |
7 | 14015562024363513 |
oct | 1372421314730601 |
9 | 225473870564273 |
10 | 52400936432001 |
11 | 15773126587513 |
12 | 5a6379b7068a9 |
13 | 2331505606851 |
14 | cd230c77bbb3 |
15 | 60d10685c3d6 |
hex | 2fa88b33b181 |
52400936432001 has 8 divisors (see below), whose sum is σ = 69879918000064. Its totient is φ = 34927956242640.
The previous prime is 52400936431913. The next prime is 52400936432017. The reversal of 52400936432001 is 10023463900425.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 52400936432001 - 225 = 52400902877569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52400936432071) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1500324301 + ... + 1500359226.
It is an arithmetic number, because the mean of its divisors is an integer number (8734989750008).
Almost surely, 252400936432001 is an apocalyptic number.
It is an amenable number.
52400936432001 is a deficient number, since it is larger than the sum of its proper divisors (17478981568063).
52400936432001 is a wasteful number, since it uses less digits than its factorization.
52400936432001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3000689351.
The product of its (nonzero) digits is 155520, while the sum is 39.
The spelling of 52400936432001 in words is "fifty-two trillion, four hundred billion, nine hundred thirty-six million, four hundred thirty-two thousand, one".
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