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524136312113 = 5973121694059
BaseRepresentation
bin1111010000010001111…
…01010110110100110001
31212002212221221102000012
413220020331112310301
532041412343441423
61040441312104305
752603405100261
oct7501075266461
91762787842005
10524136312113
11192315313a87
12856b8235095
133a56c76296b
141b5229c37a1
15d979a9d078
hex7a08f56d31

524136312113 has 8 divisors (see below), whose sum is σ = 540321626400. Its totient is φ = 508194386208.

The previous prime is 524136312103. The next prime is 524136312127. The reversal of 524136312113 is 311213631425.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 524136312113 - 28 = 524136311857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 524136312113.

It is not an unprimeable number, because it can be changed into a prime (524136312103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60842723 + ... + 60851336.

It is an arithmetic number, because the mean of its divisors is an integer number (67540203300).

Almost surely, 2524136312113 is an apocalyptic number.

It is an amenable number.

524136312113 is a deficient number, since it is larger than the sum of its proper divisors (16185314287).

524136312113 is a wasteful number, since it uses less digits than its factorization.

524136312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121694191.

The product of its digits is 12960, while the sum is 32.

Adding to 524136312113 its reverse (311213631425), we get a palindrome (835349943538).

The spelling of 524136312113 in words is "five hundred twenty-four billion, one hundred thirty-six million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 59 73 4307 121694059 7179949481 8883666307 524136312113