Base | Representation |
---|---|
bin | 100110001001000011111… |
… | …1101010100110100101001 |
3 | 200120010212211022120022012 |
4 | 1030102013331110310221 |
5 | 1141341401110220403 |
6 | 15052112324405305 |
7 | 1050506100110012 |
oct | 114220775246451 |
9 | 20503784276265 |
10 | 5242141101353 |
11 | 17411a7a97952 |
12 | 707b66546835 |
13 | 2c0440c14770 |
14 | 141a14540009 |
15 | 91560612ed8 |
hex | 4c487f54d29 |
5242141101353 has 32 divisors (see below), whose sum is σ = 5919564309120. Its totient is φ = 4609531906560.
The previous prime is 5242141101299. The next prime is 5242141101433. The reversal of 5242141101353 is 3531011412425.
It is a cyclic number.
It is not a de Polignac number, because 5242141101353 - 238 = 4967263194409 is a prime.
It is a super-3 number, since 3×52421411013533 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5242141101553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 70622183 + ... + 70696371.
It is an arithmetic number, because the mean of its divisors is an integer number (184986384660).
Almost surely, 25242141101353 is an apocalyptic number.
It is an amenable number.
5242141101353 is a deficient number, since it is larger than the sum of its proper divisors (677423207767).
5242141101353 is a wasteful number, since it uses less digits than its factorization.
5242141101353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77369.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 5242141101353 its reverse (3531011412425), we get a palindrome (8773152513778).
The spelling of 5242141101353 in words is "five trillion, two hundred forty-two billion, one hundred forty-one million, one hundred one thousand, three hundred fifty-three".
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