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52431613433 is a prime number
BaseRepresentation
bin110000110101001010…
…101110110111111001
312000100001022221011122
4300311022232313321
51324334443112213
640030423235025
73534206234513
oct606512566771
9160301287148
1052431613433
1120266308231
12a1b32a8a75
134c37776b44
14277565cbb3
15156d0b2d08
hexc352aedf9

52431613433 has 2 divisors, whose sum is σ = 52431613434. Its totient is φ = 52431613432.

The previous prime is 52431613417. The next prime is 52431613447. The reversal of 52431613433 is 33431613425.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34467036409 + 17964577024 = 185653^2 + 134032^2 .

It is a cyclic number.

It is not a de Polignac number, because 52431613433 - 24 = 52431613417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52431613393 and 52431613402.

It is not a weakly prime, because it can be changed into another prime (52431633433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26215806716 + 26215806717.

It is an arithmetic number, because the mean of its divisors is an integer number (26215806717).

Almost surely, 252431613433 is an apocalyptic number.

It is an amenable number.

52431613433 is a deficient number, since it is larger than the sum of its proper divisors (1).

52431613433 is an equidigital number, since it uses as much as digits as its factorization.

52431613433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 77760, while the sum is 35.

The spelling of 52431613433 in words is "fifty-two billion, four hundred thirty-one million, six hundred thirteen thousand, four hundred thirty-three".